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The Math Thread

PostPosted: December 11th, 2014, 3:48 pm
by lordpat
Seeing how a lot of people in this forum like Math, I thought "why not making a math thread?" And here it is!




Image


Weather you need help or have a question, or want to show something cool, or want to post a math puzzle, or anything your imagine. And no, I am not coming with a math pun.


Ok, fine. If you ever wondered why, just calculate y, and if you wonder again, calculate x (or z)!

Re: The Math Thread

PostPosted: December 12th, 2014, 3:34 am
by l.m
NAN




IT'S TIME

Re: The Math Thread

PostPosted: December 12th, 2014, 4:40 am
by Konradix
Aka the thread Nan hates. Add that to the subtitle :P

Re: The Math Thread

PostPosted: December 12th, 2014, 5:27 am
by NanTheDark
You should have made this thread sooner. I'm gonna face my fate in... *looks at wristwatch* 20 minutes. -_-

This thread will probably come in handy to other peoples though.

Also, now that I see you guys directly reference me like this, I feel like I'm popular. :3

Re: The Math Thread

PostPosted: December 12th, 2014, 6:33 am
by l.m
when i remember about math i think of nan

so nan is popular now, because he hates math

Re: The Math Thread

PostPosted: December 12th, 2014, 7:03 am
by lordpat
Best of luck Nan!

So I thought I might start with a puzzle that is not very hard (just for a warm up), but it is pretty intresting, showing that probability really is something counterintuitive.

Girl or boy?
In a two-child family, one child is a boy. What is the probability that the other child is a girl? What if the older child is a boy?

EDIT: Oh, credit: mathforum.org

A very simple puzzle that, at least to me, is very intresting. It reminds me to the Monty Hall problem.

Re: The Math Thread

PostPosted: December 12th, 2014, 7:18 am
by Supershroom
*Thumbs up to this topic* ...

... but this one is too easy. The probability for a girl or a boy stays the same no matter which sex any previous child has. Here's a slightly harder one:

Be sure not to bet too much. I show you three cards, one has two black sides, another has two red sides, and the third has both one black side and one red side. I put the cards under a hat, take one out randomly (or better: let you take one out) so that only the front side is visible, and then I bet 10 bucks that the back side has the same colour as the front side. How many bucks shall you hold up to let this be a fair bet?

Joke as addition: show
A mathematician has found a wonderful proof and wants to hang it up as a picture on the wall. Sadly there's no one else present so he has to nail it on his own. He holds the nail with its head pointing to the wall. Before he wants to hit it, he looks at it, and stops short. He thinks ... and thinks ... after five minutes he comes to the conclusion:

This is a nail for the opposite wall.

Re: The Math Thread

PostPosted: December 12th, 2014, 7:55 am
by Konradix
20/3 bucks

Re: The Math Thread

PostPosted: December 12th, 2014, 7:57 am
by Supershroom
Maybe you have the right idea, but I strongly believe this is incorrect

One more try.

Re: The Math Thread

PostPosted: December 12th, 2014, 8:01 am
by lordpat
It does affect, Shroom. Try putting it up as a traditional probability problem. The answer may surprise you.